An outlet can be GFCI if there's a GFCI at some point on the circuit, could even have a GFCI breaker - you'd need to check the other outlets on the line and the breaker; should do that regardless to know how to reset the line if you ever trip the GFCI
Just get one of these. They will do what you're looking to do here, and it's a useful thing to have in general. It's also pretty cheap, $13 at home depot, or $25 for the set that also has the voltage tester.
put a 10K ohm resistor across from hot to ground. This will draw enough ground fault current to pop the GFCI but won't trip the regular circuit breaker
I have a fourth grade education. I assume that you're saying that during the peak part of the AC sine waveform, the voltage will rise high enough (~170v?) and for long enough (a few milliseconds) to trip the gfci?
to simplify just do this. 10 mA will trip any GFCI that works. r = 120/0.01 = 12k ohms. if the GFCI does not trip, that resistor will have to dissipate P= VI = 120 * 0.01 = 1.2 watts so at least get a 1 watt version, if not a 5 watt which won't burn your fingers.
An outlet can be GFCI if there's a GFCI at some point on the circuit, could even have a GFCI breaker - you'd need to check the other outlets on the line and the breaker; should do that regardless to know how to reset the line if you ever trip the GFCI
Just get one of these. They will do what you're looking to do here, and it's a useful thing to have in general. It's also pretty cheap, $13 at home depot, or $25 for the set that also has the voltage tester.
put a 10K ohm resistor across from hot to ground. This will draw enough ground fault current to pop the GFCI but won't trip the regular circuit breaker
Get a gfci tester or try a ~25k resistor from live to ground.
120v / 25000 ohm = 4.8milliamps
That might not be enough current to reliably trip a GFCI
That’s 120v RMS, not peak-to-peak.
So, think about that and what you posted for a bit.
I have a fourth grade education. I assume that you're saying that during the peak part of the AC sine waveform, the voltage will rise high enough (~170v?) and for long enough (a few milliseconds) to trip the gfci?
Can you give me a clue?
to simplify just do this. 10 mA will trip any GFCI that works. r = 120/0.01 = 12k ohms. if the GFCI does not trip, that resistor will have to dissipate P= VI = 120 * 0.01 = 1.2 watts so at least get a 1 watt version, if not a 5 watt which won't burn your fingers.
don't argue RMS vs peak.
Take an old extension cord. Cut it in half hamburger style. Strip it. Plug it in. Then touch the wires together.
Quit being a retarded moron and just buy a $3 tester you stupid fucking nonwhite useless pieces of shit
>connect neutral to earth terminal
>tester says it's OK
Literally worse than useless.
Get a tester from your local home improvement store, they're like 15$, either the receptacle will be fed from a GFI breaker or from a GFI upstream
Trip the gfci outlet/breaker you think it's connected to(test button), check for power. If it has power it's not protected by one of the gfcis
Practical deduction is for boomers. You're supposed to go online and ask someone to link a tutorial now.